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07-ilang-weight / 05-inertia-of-mark
05inertia of markverified

Determines, for a moving body with its own mark and three couplings, whether its inertia is its cost over the square of one speed for all levels, and whether weight over inertia is level-independent.

Version 1 · earlier version; the current one is v4 · External review, round 1: major errors

# Inertia of a body with its own mark against its cost

- **Subproject:** 07-ilang-weight
- **Package:** 05-inertia-of-mark
- **Version:** v1
- **Mode:** new
- **Date:** 2026-10-21

## Setup and assumptions

**Description (assumption, M8).** The ring of $L\ge5$ places carries $N_f\ge1$ identical field objects ($c=+1$) with own term $C_1$. $\Phi_x$ is their number at $x$, and $n=N_f/L$. One Model D body sits on the same ring, at clock level $k$ with half-gap $M_k=m+2\pi k/(N\lambda_0)$. It is coupled by (a), (c) or the full grip (FG), with real $\gamma\neq0$; records at $\kappa\to0$. As in 03-weight-of-mark, $\theta=1$ for (a) and (c), and $\theta=0$ for FG. The total contracts of FG and (a) differ by the rest and clock term $B$, so they are different descriptions, not M6 replacements.

**Notation.**
- $g:=\gamma M_k$, $g_\sigma:=\sigma g$ (the $g_b$ of (3.4)), and $\varkappa_k:=|g|L/t_f$.
- $\varepsilon_q=2t_f(1-\cos q)$ for $q\in Q:=\frac{2\pi}L\{1,\dots,L-1\}$, $\varepsilon_1:=\varepsilon_{2\pi/L}$, and $\langle f\rangle_q:=\frac1L\sum_{q\in Q}f(q)$.
- $s_1:=\langle\varepsilon_q^{-1}\rangle_q=\ell_0/t_f$ with $\ell_0=\Lambda^+(0)=(L^2-1)/(12L)$, $s_2:=\langle\varepsilon_q^{-2}\rangle_q$, and $S_2:=\langle(1+\cos q)\varepsilon_q^{-2}\rangle_q=2s_2-s_1/(2t_f)$.
- For one field object at place $r$ relative to the body: $h(g):=C_1+gP_0$, with lowest eigenvalue $\varepsilon_0(g)$ and positive ground vector $\varphi_g$ (Perron–Frobenius). $\Omega_\sigma:=\varphi_{g_\sigma}^{\otimes N_f}$.
- Inertia $\mu_{k,\sigma}:=1/E''_{k,\sigma}(0)$. Held cost (3.4): $\mathrm{Cost}_{k,\sigma}=\theta\sigma M_k+N_f[\varepsilon_0(g_\sigma)-\varepsilon_0(0)]$.

**Assumptions.**
- **A1 (M9, field state).** At $\tau=0$ the field is in $\Omega_\sigma$, the lowest state of the branch-$\sigma$ block (the lowest state adapted to the body). The dressed level is its continuation in $\tau$ and $P$.
- **A2 (A13, regime).**
  - The curvature is computed at order $\tau^2$, under the isolation condition (5.4) for FG and (6.4) at $\tau=0$ for (a) and (c).
  - FG is expanded in the weak-mark regime **R1**: $N_f\varkappa_k\ll1$.
  - (a) and (c) are expanded in $\gamma$ at fixed $L,N_f$, at leading order in $\tau$.
- **A3 (standard mathematics).** Rayleigh–Schrödinger (RS) perturbation theory for a nondegenerate isolated eigenvalue: for $\lVert V\rVert<d/2$, with $d$ the distance to the rest of the unperturbed spectrum, the eigenvalue continues analytically (Kato). Fourier sums on the ring, for example $\sum_{j=1}^{L-1}\sin^{-2}(\pi j/L)=(L^2-1)/3$, and Perron–Frobenius.

**Inputs used:** (6.1), (6.4), (6.10), (6.12) of 06-ilang-source/06-own-mark; (2.14) of 02-two-free-bodies; (3.4), (3.12), (3.13) of 03-weight-of-mark; (7.7) of 06-ilang-source/07-dressed-fall. (6.5) of 06-ilang-source/06-own-mark is quoted but not needed, because (5.2) is exact in $\gamma$.

## Derivation

### Step 1. Sector contract; the full grip

Place the body at $x$ and the field objects at $x+r_i$. The vectors $L^{-1/2}\sum_xe^{iPx}\lvert x,s\rangle\lvert\{x+r_i\}\rangle$ span the sector of total label $P$, since the total contract commutes with the joint translation. In these coordinates the field hopping acts on the $r_i$ unchanged, and the pair term becomes $g_\sigma\Phi_0$ on branch $\sigma$ ($\Phi_r$ counts the objects at relative place $r$). The hop $\lvert x+1\rangle\langle x\rvert$ maps the sector vector with $\{r_i\}$ to $e^{-iP}$ times the one with $\{r_i-1\}$, and the bond factor $\frac12(\Phi_x+\Phi_{x+1})$ of (c) acts before the hop, at relative places $0$ and $1$.

On level $k$ (the clock label commutes with the total contract), (6.1) holds with

$$
\hat C^{(0)}=\sum_{\sigma=\pm}\lvert\sigma\rangle\langle\sigma\rvert\otimes\hat C^{(0)}_\sigma,\quad \hat C^{(0)}_\sigma=\theta\sigma M_k+C_1+g_\sigma\Phi_0,\qquad \hat C^{(+)}=\frac\tau2(-i\sigma_1)\otimes K,\quad K=\begin{cases}T_-&\text{(a), FG}\\ T_-\bigl(1+\frac\gamma2(\Phi_0+\Phi_1)\bigr)&\text{(c)}\end{cases}
\tag{5.1}
$$

with $T_\pm$ shifting all relative places by $\pm1$. For FG, (6.1) applies unchanged: only $\hat C^{(0)}$ changes ($\theta=0$).

The reflection $\mathcal R:r\to-r$ leaves $\hat C^{(0)}_\sigma$ and $\Omega_\sigma$ invariant and maps $K$ to $K^\dagger$ (since $T_+^\dagger\Phi_rT_+=\Phi_{r-1}$). All these operators are real in the place basis.

### Step 2. Curvature at order $\tau^2$ and the branch splitting

$V(P):=e^{-iP}\hat C^{(+)}+e^{iP}\hat C^{(+)\dagger}$ flips the branch and has $\lVert V\rVert\le\tau\lVert K\rVert$. At $\tau=0$ the level is $E^0_\sigma=\theta\sigma M_k+N_f\varepsilon_0(g_\sigma)$, with vector $\lvert\sigma\rangle\otimes\Omega_\sigma$ (A1); $d_{k,\sigma}$ is its distance to the rest of the spectrum of $\hat C^{(0)}$.

The first RS order vanishes. The second uses $R:=(E^0_\sigma-\hat C^{(0)}_{-\sigma})^{-1}$, $(-i)^2=i^2=-1$ and expectation values in $\Omega_\sigma$:

$$E_{k,\sigma}(P)=E^0_\sigma+\frac{\tau^2}4\bigl[\langle KRK^\dagger\rangle+\langle K^\dagger RK\rangle-2J\cos2P\bigr]+O\Bigl(\frac{\tau^4\lVert K\rVert^4}{d^3_{k,\sigma}}\Bigr).$$

Here $J:=\langle KRK\rangle=\langle K^\dagger RK^\dagger\rangle$ is real, by $\mathcal R$ and reality. Hence, exactly in $\gamma$:

$$E''_{k,\sigma}(0)=2\tau^2J_{k,\sigma}+O\Bigl(\frac{\tau^4\lVert K\rVert^4}{d^3_{k,\sigma}}\Bigr),\qquad J_{k,\sigma}=\langle\Omega_\sigma\vert K\,(E^0_\sigma-\hat C^{(0)}_{-\sigma})^{-1}K\vert\Omega_\sigma\rangle .\tag{5.2}$$

The lowest eigenvector of $\hat C^{(0)}_{-\sigma}$ is $\Omega_{-\sigma}$, and $E^0_\sigma-E^0_{-\sigma}=\mathrm{Cost}_{k,\sigma}-\mathrm{Cost}_{k,-\sigma}$ exactly. Define:
- $R_k:=\frac12(\mathrm{Cost}_{k,+}-\mathrm{Cost}_{k,-})$ and $C^{\rm ev}_k:=\frac12(\mathrm{Cost}_{k,+}+\mathrm{Cost}_{k,-})$;
- $a_{k,\sigma}:=\langle\Omega_{-\sigma}\vert K\vert\Omega_\sigma\rangle$, equal to $\langle\Omega_{-\sigma}\vert K^\dagger\vert\Omega_\sigma\rangle$ by $\mathcal R$.

Separating the term of $\Omega_{-\sigma}$ in the spectral sum of $R$ gives

$$\mathrm{Cost}_{k,\sigma}=\sigma R_k+C^{\rm ev}_k,\qquad J_{k,\sigma}=\frac{a_{k,\sigma}^2}{2\sigma R_k}+J^{\rm exc}_{k,\sigma},\qquad \mu_{k,\sigma}=\frac{\sigma R_k}{\tau^2\bigl(a^2_{k,\sigma}+2\sigma R_kJ^{\rm exc}_{k,\sigma}\bigr)}\quad\text{at order }\tau^{-2},\tag{5.3}$$

where $J^{\rm exc}$ is the sum over the excited eigenvectors of $\hat C^{(0)}_{-\sigma}$. The inertia is set by the branch-odd part $R_k$ of the cost. The even part $C^{\rm ev}_k$ enters only through $a$ and $J^{\rm exc}$.

**M6.** $\mu_{k,\sigma}$, $R_k$ and the level differences of $C^{\rm ev}_k$ are curvatures and eigenvalue differences of one total contract. $C^{\rm ev}_k$ itself is fixed only up to the level-independent reference, the description without the body.

**Dressed level at $P=0$.** $E_{k,\sigma}(0)-E^0_\sigma=\frac{\tau^2}4\langle w\vert R\vert w\rangle$ with $w=(K^\dagger-K)\Omega_\sigma$, and $w\perp\Omega_{-\sigma}$ by $\mathcal R$. So it is $O(\tau^2)$, without the factor $1/R_k$.

### Step 3. Isolation for the full grip (item 1)

At $\tau=0$, $\hat C^{(0)}_\sigma=C_1+g_\sigma\Phi_0$ acts on $N_f$ non-interacting bosons, and its eigenvalues are sums of eigenvalues of $h(g_\sigma)$. Call $\sigma_l:=-\operatorname{sign}\gamma$ the lower branch ($g_{\sigma_l}=-|g|$) and $\sigma_u:=-\sigma_l$ the upper one.
- **Splitting.** $\hat C^{(0)}_{\sigma_u}-\hat C^{(0)}_{\sigma_l}=2|g|\Phi_0\ge0$, and $\Omega_{\sigma_u}$ has positive density at $r=0$. Hence $\Delta_b:=E^0_{\sigma_u}-E^0_{\sigma_l}=2|R_k|>0$.
- **Lower level.** By Perron–Frobenius, $E^0_{\sigma_l}$ is the nondegenerate lowest eigenvalue of $\hat C^{(0)}$.
- **Distances.** With $\varepsilon^\pm_1$ the first excitation energy of $h(\pm|g|)$: $d_{k,\sigma_l}=\min(\Delta_b,\varepsilon^-_1)$, and, if $\Delta_b<\varepsilon^-_1$, $d_{k,\sigma_u}=\min(\Delta_b,\varepsilon^-_1-\Delta_b,\varepsilon^+_1)$.

For FG $\lVert K\rVert=1$, so by Kato (5.2) holds for $\tau<d/2$. In R1, $\Delta_b=2n|g|(1+O(\varkappa_k^2))$ by (5.5), and $\varepsilon^\pm_1=\varepsilon_1(1+O(\varkappa_k))$. The condition reads

$$\tau<\tfrac12d_{k,\sigma},\qquad d_{k,\sigma}\simeq\begin{cases}\min\bigl(2n|\gamma|M_k,\ \varepsilon_1\bigr),&\sigma\gamma<0,\\ \min\bigl(2n|\gamma|M_k,\ \varepsilon_1-2n|\gamma|M_k\bigr),&\sigma\gamma>0,\ 2n|\gamma|M_k<\varepsilon_1,\end{cases}\qquad \varepsilon_1=2t_f\Bigl(1-\cos\frac{2\pi}L\Bigr).\tag{5.4}$$

Where it fails:
1. **$\gamma\to0$, both branches.** $d\to0$: without coupling the FG body is gapless, with band $\pm\tau\lvert\sin P\rvert$.
2. **Upper branch, $N_f\ge2$.** As $2n|\gamma|M_k$ approaches $\varepsilon_1$, the upper level crosses the lowest excited level of the other branch (the branches do not mix at $\tau=0$). Beyond that it crosses multi-object excitations at isolated values of $\gamma$.
3. **$N_f=1$: no crossing.** The even eigenvalues of $h(\pm|g|)$ solve $\pm1/|g|=\langle0\vert(E-C_1)^{-1}\vert0\rangle$, which decreases between consecutive poles; the odd ones are $\ge-2t_f\cos(2\pi/L)$. Hence $\varepsilon_0(|g|)$ lies strictly between the two lowest eigenvalues of $h(-|g|)$. The upper branch is isolated for every $\gamma\neq0$, with $d_{k,\sigma_u}\to0$ as $\varkappa_k\to\infty$.
4. **$L\to\infty$ at fixed $n,\gamma$.** $\varepsilon_1\to0$ and the upper branch fails. The lower branch stays isolated, with $d_{k,\sigma_l}\to\sqrt{4t_f^2+\gamma^2M_k^2}-2t_f$ (the binding gap of the infinite chain; $\Delta_b\propto N_f\to\infty$).

### Step 4. Weak-mark expansion

RS for $h(g)=h(0)+gP_0$ in plane waves $\lvert q\rangle$, with $\langle q\vert P_0\vert q'\rangle=1/L$ and $u:=\lvert q{=}0\rangle$, gives

$$
\begin{aligned}
&\varphi_g=u+g\varphi^{(1)}+O(g^2),\quad \langle q\vert\varphi^{(1)}\rangle=-\frac1{L\varepsilon_q},\qquad \varepsilon_0(g)=-2t_f+\frac gL-\frac{g^2s_1}L+\frac{g^3}L\Bigl(s_1^2-\frac{s_2}L\Bigr)+O(g^4),\\
&R_k=\theta M_k+n\gamma M_k\bigl[1+\gamma^2M_k^2(s_1^2-s_2/L)\bigr]+O(\gamma^5),\qquad C^{\rm ev}_k=-n\gamma^2M_k^2\,\ell_0/t_f+O(\gamma^4),\\
&a^2_{k,\sigma}=(1+\theta_c\gamma n)^2-2ng^2S_2+O(\gamma^3),\qquad J^{\rm exc}_{k,\sigma}=2n\Bigl\langle\frac{\cos q\,(1+\cos q)\,u_q^2}{2\sigma R_k-\varepsilon_q}\Bigr\rangle_q+O(\gamma^3),
\end{aligned}\tag{5.5}
$$

with $\theta_c=1$ for (c) and $0$ otherwise. The vertex is $u_q=-g_\sigma/\varepsilon_q$ for (a) and FG, and $u_q=\gamma/2-g_\sigma/\varepsilon_q$ for (c). Reasons:
- **$\varepsilon_0(g)$.** In the third RS order all matrix elements equal $g/L$, so $E^{(3)}=(g/L)^3[(\sum_q\varepsilon_q^{-1})^2-\sum_q\varepsilon_q^{-2}]$. $R_k$ and $C^{\rm ev}_k$ are the odd and even parts in $g$ of (3.4).
- **$a$ for (a) and FG.** $a=\alpha^{N_f}$ with
$$\alpha:=\langle\varphi_{-g_\sigma}\vert T_-\varphi_{g_\sigma}\rangle=1-g^2\bigl(\lVert\varphi^{(1)}\rVert^2+\langle\varphi^{(1)}\vert T_+\varphi^{(1)}\rangle\bigr)+O(g^4)=1-g^2S_2/L+O(g^4).$$
  $\alpha$ is even in $g$ by $\mathcal R$. The $O(g)$ terms vanish because $T_\pm u=u$ and $\varphi^{(1)}\perp u$.
- **$a$ for (c).** It gains $\frac\gamma2N_f\alpha^{N_f-1}\bigl[\varphi_{-g_\sigma}(-1)\varphi_{g_\sigma}(0)+\varphi_{-g_\sigma}(0)\varphi_{g_\sigma}(1)\bigr]=\gamma n+O(\gamma^3)$. The $O(g)$ parts cancel because $\varphi^{(1)}$ is even in $r$.
- **$J^{\rm exc}$.** The component of $K\Omega_\sigma$ with one object excited is $N_f^{1/2}$ times a one-object vector $\eta$, with $\langle q\vert\eta\rangle=L^{-1}(1+e^{iq})u_q+O(\gamma^2)$. Its sources:
  - $T_-\varphi_{g_\sigma}-\alpha\varphi_{-g_\sigma}=g_\sigma(1+T_-)\varphi^{(1)}$;
  - for (c), also $\frac\gamma2T_-(P_0+P_1)u$, with $\langle q\vert T_-(P_0+P_1)\vert u\rangle=(1+e^{iq})/L$.

  The corresponding component of $K^\dagger\Omega_\sigma$ is its $\mathcal R$-image, and the excitation energy is $\varepsilon_q+O(\gamma)$. For even $f$, $\sum_q(1+e^{iq})^2f(q)=\sum_q2\cos q(1+\cos q)f(q)$. Two-object excitations contribute $O(\gamma^4)$.

The denominators stay away from zero by R1 ($|2R_k|<\varepsilon_1$) for FG, and by (6.4) at $\tau=0$ ($2M_k\neq\varepsilon_q$) for (a) and (c).

### Step 5. Item 1: curvature of the full grip

Put $\theta=\theta_c=0$ in (5.5):
- $2\sigma R_k=2ng_\sigma[1+g^2(s_1^2-s_2/L)]$;
- $a^2=1-2ng^2S_2$;
- $2\sigma R_kJ^{\rm exc}=O(n^2|g|^3\langle\varepsilon_q^{-3}\rangle_q)=O(N_f^2\varkappa_k^3)$.

By (5.2) and (5.3), under (5.4) and R1:

$$E''_{k,\sigma}(0)=\frac{\tau^2}{n\sigma\gamma M_k}\Bigl[1-\gamma^2M_k^2K_L+O(N_f^2\varkappa_k^3)\Bigr]+O\Bigl(\frac{\tau^4}{d_{k,\sigma}^3}\Bigr),\qquad K_L=2nS_2+s_1^2-\frac{s_2}L\simeq\frac{(N_f+1)L^2}{180\,t_f^2}.\tag{5.6}$$

So $\gamma^2M_k^2K_L\simeq(N_f+1)\varkappa_k^2/180$. The leading term is the curvature $\tau^2/(\sigma\tilde M)$ of a Model D body with rest half-gap $\tilde M=n\gamma M_k$: in FG the mean density of the field supplies the rest term. Beyond R1, (5.2) still gives the order-$\tau^2$ curvature wherever $d_{k,\sigma}>2\tau$; for the lower branch this holds at every $\gamma\neq0$ for small enough $\tau$. The check of (5.2) and (5.6) against the exact dressed level is under "Code".

### Step 6. Item 2: inertia against cost

**Which cost.** The held cost (3.4) enters every comparison. By Step 2, $E_{k,\sigma}(0)-N_f\varepsilon_0(0)-\mathrm{Cost}_{k,\sigma}=O(\tau^2)$, without the factor $1/R_k$. Divided by $v^2$ it is $O(\tau^0)$, below the order $\tau^{-2}$ of $\mu$. So the dressed level gives the same answers here, and the bracket of (6.12) reduces to the held cost as $\tau\to0$.

**Criterion (M6).** One speed $v$ for all levels and branches means that $D_{k,\sigma}:=\mu_{k,\sigma}-\mathrm{Cost}_{k,\sigma}/v^2$ does not depend on $(k,\sigma)$; the constant is the reference of the cost. Equivalently, every difference of inertia between levels and branches equals the difference of cost divided by $v^2$.

**Leading order.**
- FG: by (5.3) and (5.5), $a^2=1+O(\gamma^2)$ and $2\sigma R_kJ^{\rm exc}=O(\gamma^3)$, so $\mu=\sigma R_k/\tau^2+O(\gamma^3)$.
- (a), (c): (2.14), with $\mathrm{Cost}=\sigma R_k+O(\gamma^2)$.

Together:

$$\mu_{k,\sigma}=\frac{\mathrm{Cost}_{k,\sigma}}{v^2}+O(\gamma^2)\ \text{ for every }k,\sigma,\qquad v=\tau\ \text{ (a), FG},\qquad v=\tau(1+\gamma n)\ \text{ (c)}.\tag{5.7}$$

For FG the leading term is of order $\gamma$: $\mu=n\sigma\gamma M_k/\tau^2$.

**Identification of $v$.** $v$ is the slope at $P\to0$ of the band of the motion term alone, with its mean-field factor: $\pm v\lvert\sin P\rvert$. This is the $M_k\to0$ limit of the mean-field bands $(M_k^2(1+\gamma n)^2+\tau^2\sin^2P)^{1/2}$ (a), $(1+\gamma n)(M_k^2+\tau^2\sin^2P)^{1/2}$ (c) and $(n^2\gamma^2M_k^2+\tau^2\sin^2P)^{1/2}$ (FG).
- In the regime every level has a nonzero mean-field half-gap, so its group velocity stays below $v$; no level attains it.
- For FG, $\pm\tau\lvert\sin P\rvert$ is the band of the description at $\gamma=0$.
- $v$ does not depend on $t_f$, so it is not fixed by the field band $-2t_f\cos q$.

**Order $\gamma^2$.** Changing $v$ at order $\gamma^2$ ($v^2\to v^2(1+b\gamma^2)$) adds $b\gamma^2\sigma M_k/\tau^2+O(\gamma^3)$ to $D$ for (a) and (c), and only $O(\gamma^3)$ for FG.

*FG.* By (5.3) and (5.5):

$$D_{k,\sigma}=-\frac{C^{\rm ev}_k}{\tau^2}+O(\gamma^3)=\frac{n\ell_0\gamma^2M_k^2}{t_f\tau^2}+O(\gamma^3),\qquad (\mu_{k,\sigma}-\mu_{k',\sigma'})-\frac{\mathrm{Cost}_{k,\sigma}-\mathrm{Cost}_{k',\sigma'}}{\tau^2}=\frac{n\ell_0\gamma^2(M_k^2-M_{k'}^2)}{t_f\tau^2}+O(\gamma^3).\tag{5.8}$$

The branch differences at one level still agree through $O(\gamma^2)$, but the level differences do not. The inertia follows the branch-odd part of the cost, not its even part (the second-order mark).

*(a) and (c).* With $v$ of (5.7), (5.3) and (5.5) give
$$D_{k,\sigma}=-\frac{C^{\rm ev}_k}{\tau^2}+\frac{\sigma M_k}{\tau^2}\bigl(2ng^2S_2-2\sigma M_kJ^{\rm exc}_{k,\sigma}\bigr)+O(\gamma^3).$$
The bracket equals $\frac{n\gamma^2M_k^2}{t_f^2}\bigl\langle\frac{(1+\cos q)(\sigma M_k-t_f)}{(1-\cos q)(2\sigma M_k-\varepsilon_q)}\bigr\rangle_q$ for (a), using $1-\frac{2\sigma M\cos q}{2\sigma M-\varepsilon_q}=\frac{2(1-\cos q)(\sigma M-t_f)}{2\sigma M-\varepsilon_q}$. For (c) it equals $\frac{n\gamma^2M_k}{2t_f^2}\bigl\langle\frac{(1+\cos q)(M_k+\sigma t_f\cos q)}{1-\cos q}\bigr\rangle_q$: the vertex $(\varepsilon_q-2\sigma M_k)^2/(4\varepsilon_q^2)$ cancels the denominator. Hence

$$
\begin{aligned}
D^{(a)}_{k,\sigma}&=\frac{n\gamma^2M_k^2}{2t_f^2\tau^2}\Bigl\langle\frac1{1-\cos q}\Bigl[t_f+\frac{2M_k(1+\cos q)(M_k-\sigma t_f)}{2\sigma M_k-\varepsilon_q}\Bigr]\Bigr\rangle_q+O(\gamma^3),\\
D^{(c)}_{k,\sigma}&=\frac{n\gamma^2M_k^2}{2t_f^2\tau^2}\Bigl\langle\frac{t_f(1+\cos q+\cos^2q)+\sigma M_k(1+\cos q)}{1-\cos q}\Bigr\rangle_q+O(\gamma^3).
\end{aligned}\tag{5.9}
$$

For $\sigma=+$, this is the $\tau\to0$ value of $-[M_k^2\Delta''_{k,+}/\tau^2+\Delta_{k,+}]/\tau^2$, the term of (6.12) that the quoted inputs leave unevaluated.

Two limits of (5.9):
- **$t_f\gg M_kL^2$** (all $\varepsilon_q\gg M_k$). $D^{(a)}=\frac{n\ell_0\gamma^2M_k^2}{t_f\tau^2}(1+O(M_kL^2/t_f))$ and $D^{(c)}=\frac{n\gamma^2M_k^2}{2t_f\tau^2}\langle\frac{1+\cos q+\cos^2q}{1-\cos q}\rangle_q(1+O(M_kL^2/t_f))$. Both are branch-even and proportional to $M_k^2$; the branch-odd term $b\gamma^2\sigma M_k/\tau^2$ cannot remove them.
- **$t_f\ll M_k$.** Both equal $\sigma\frac{n\gamma^2M_k^3}{2t_f^2\tau^2}\langle\frac{1+\cos q}{1-\cos q}\rangle_q(1+O(t_f/M_k))$. They are branch-odd but proportional to $M_k^3$, which $b\gamma^2\sigma M_k$ removes for at most one value of $M_k$.

So there is no single $v$ at order $\gamma^2$ in either limit. Away from the resonances $2M_k=\varepsilon_q$, $D$ is analytic in $t_f$, so the condition can hold at most at isolated values of $t_f$.

**Controls.**
- **(5.7).** It holds for every member of the class in the regime, so there is no control in the class. In the wider class with a branch-even clock term $\mathbb 1_2\otimes D'$ added to the body ($D'$ diagonal in the levels, not proportional to $\mathbb 1$), $\mathrm{Cost}_{k,\sigma}$ shifts by $D'_k$. $E_{k,\sigma}(P)$ shifts by the same $D'_k$ at every $P$, so $\mu$ is unchanged and (5.7) fails at order $\gamma^0$.
- **(5.8), (5.9).** Control: a body with one half-gap ($D=0$, a wider class). Then $D_{k,\sigma}=D_\sigma$. For FG, $v=\tau$ holds through $O(\gamma^2)$. For (a) and (c), $b$ removes the odd part of $D_\sigma$ and the even part is a constant.
### Step 7. Item 3: weight over inertia

By (3.12) and (3.13), $\Delta W_{k,\sigma}=\mathcal W(C^{\rm mark}_{k,\sigma})$ for (a) and (c) (they coincide at $\tau=0$) and for FG ($\theta=0$). The rest term does not depend on the place, so all three share
$$C^{\rm mark}_{k,\sigma}=\mathrm{Cost}_{k,\sigma}-\theta\sigma M_k=n\sigma\gamma M_k-n\ell_0\gamma^2M_k^2/t_f+O(\gamma^3).$$
For $E''$ use (6.10), $\sigma\tau^2(1\mp\gamma n)/M_k+O(\gamma^2)$ for (a) and (c), and (5.6) for FG. With $\mathcal W(C)=FC+F_2C^2+O(C^3)$:

$$E''_{k,\sigma}(0)\,\Delta W_{k,\sigma}=\tau^2F\,\Lambda\,\bigl[1+\sigma\gamma M_k\,\Xi+O(\gamma^2)\bigr]+O(g_s^2),\qquad \Xi:=\frac{nF_2}F-\frac{\ell_0}{t_f}=-\frac{[\ell^2+2\ell_0\ell-2\ell^{(2)}/\lvert X_f\rvert]}{2t_f\,[\ell]},\tag{5.10}$$

with $\Lambda=1$ for FG, $n\gamma(1-\gamma n)$ for (a) and $n\gamma(1+\gamma n)$ for (c).
- **Leading order.** The product is the same for all levels and both branches.
- **First dependence.** At relative order $\gamma$, $\sigma\gamma M_k\Xi$, with one coefficient $\Xi$ for all three couplings. Since $\ell,\ell_0=O(L)$ and $\ell^{(2)}=O(L^3)$, $\lvert\gamma M_k\Xi\rvert=O(\varkappa_k)$.

The mechanism: $E''\Delta W\propto\mathcal W(C^{\rm mark})/R_k$. The weight follows the whole mark, nonlinearly; the inertia follows only its branch-odd part.

**(7.7) for FG.** The premises of (7.7) are:
- a start with real envelope in an isolated band;
- the held weight as the place dependence at first order in $g_s$;
- the coefficient of $\tau^2$.

FG provides all three: by (5.1)–(5.4) the band at order $\tau^2$ has the same form, $E^0_\sigma+\text{const}-\frac{\tau^2}2J\cos2P$, and $W$ is that of (3.12) with $\theta=0$. So (7.7) applies to FG with $E''$ of (5.2), and the fall from rest inherits the level dependence of (5.10).

**Controls.**
- **Leading universality.** In the wider class of bodies whose motion term carries a level-dependent factor $A\otimes f(D)$, $E''$ scales with $f(D_k)^2$ while $\Delta W$ is unchanged, so universality fails at leading order.
- **(a), (c) with unequal couplings** of the $m$ and $D$ parts (M7) also fail. For FG such unequal couplings keep $\Lambda=1$.
- **The $O(\gamma)$ dependence.** In the wider class of a body with a position-dependent rest term and no field object (A10), $E''\Delta W$ is exactly universal.
### Step 8. Item 4: the hopping of the field

Take $n,\gamma,M_k,\tau$ fixed (and $L$, unless stated).
- **$v$.** (5.7) does not depend on $t_f$.
- **Isolation, FG.** The lower branch needs only $\tau<\frac12\min(\Delta_b,\varepsilon^-_1)$. For $N_f\ge2$, the upper branch lies below the excited lower-branch levels only if $\varepsilon_1>2n|\gamma|M_k$ (leading order in $\varkappa_k$), that is $t_f>n|\gamma|M_k/(1-\cos\frac{2\pi}L)\simeq N_f|\gamma|M_kL/(2\pi^2)$. In every case $d_{k,\sigma_u}\le\varepsilon^+_1<\varepsilon_1$. R1 needs $t_f\gg N_f|\gamma|M_kL$.
- **Isolation, (a) and (c).** The denominators of (5.9) avoid zero when $\varepsilon_1>2M_k$ or $4t_f<2M_k$.
- **Size of the first level dependence.** It stays at order $\gamma^2$ in $\mu$, with relative size

$$\frac{\tau^2D_{k,\sigma}}{\sigma R_k}=\begin{cases}\sigma\gamma M_k\ell_0/t_f&\text{FG},\\ \sigma n\gamma^2M_k\ell_0/t_f\ \text{(a)},\quad \sigma n\gamma^2M_kL\,(1+O(L^{-1}))/(4t_f)\ \text{(c)},& t_f\gg M_kL^2,\\ n\gamma^2M_k^2\bigl\langle\frac{1+\cos q}{1-\cos q}\bigr\rangle_q/(2t_f^2)\simeq n\gamma^2M_k^2L/(6t_f^2)\ \text{(a), (c)},& t_f\ll M_k,\end{cases}\qquad \gamma M_k\Xi=O\Bigl(\frac{\gamma M_kL}{t_f}\Bigr).\tag{5.11}$$

- **$t_f$ large.** Every level and branch dependence of items 2 and 3 vanishes as $1/t_f$, and the body approaches the mean-field Model D body.
- **$t_f$ small against $M_k$** (with R1 kept by a small $\gamma$). FG keeps (5.8). In (a) and (c) the dependence grows as $1/t_f^2$ and becomes branch-odd.
- **$t_f$ small against $\tau$.**
  - The FG upper branch is not isolated, since $d_{k,\sigma_u}<\varepsilon_1\simeq4\pi^2t_f/L^2<2\tau$.
  - The lower branch is isolated for $t_f\ll\tau\ll|\gamma|M_k$. There $J=\langle K^\dagger\Omega_\sigma\vert R\vert K\Omega_\sigma\rangle=O(t_f^{2N_f})$: every object must move from beside the body on one side to the other side, by two hops of amplitude $t_f$. At $t_f=0$, $R$ is diagonal in places and $J=0$.
  - So $\mu\to\infty$ while $\mathrm{Cost}_{k,\sigma_l}\to-N_f|\gamma|M_k$: the inertia does not follow the cost.
- **$L\to\infty$ at fixed $n$.** $N_f\varkappa_k=n|\gamma|M_kL^2/t_f\to\infty$: R1, the upper-branch isolation and (5.6)–(5.10) fail, and the order-$\gamma^2$ level dependences grow in proportion to $L$ ($\ell_0\simeq L/12$, $\langle(1-\cos q)^{-1}\rangle_q\simeq L/6$). (5.2) and (5.3) still hold for the lower branch.

## Result

Class: one Model D body on the ring field of $N_f\ge1$ objects, $L\ge5$, couplings (a), (c) and FG, field state A1, every level $k$ and both branches.

- **(5.1)** The sector contract has the form (6.1) with $\hat C^{(0)}_\sigma=\theta\sigma M_k+C_1+g_\sigma\Phi_0$ and $\hat C^{(+)}=\frac\tau2(-i\sigma_1)\otimes K$. For FG, (6.1) applies unchanged and only $\hat C^{(0)}$ changes ($\theta=0$).
- **(5.2)** Wherever the $\tau=0$ level is isolated at distance $d_{k,\sigma}$: $E''_{k,\sigma}(0)=2\tau^2J_{k,\sigma}+O(\tau^4\lVert K\rVert^4/d^3_{k,\sigma})$, exact in $\gamma$.
- **(5.3)** $\mathrm{Cost}_{k,\sigma}=\sigma R_k+C^{\rm ev}_k$ and, at order $\tau^{-2}$, $\mu_{k,\sigma}=\sigma R_k/[\tau^2(a^2_{k,\sigma}+2\sigma R_kJ^{\rm exc}_{k,\sigma})]$. The inertia is set by the branch-odd part $R_k$ of the held cost. The dressed level at $P=0$ differs from the held level by $O(\tau^2)$, without the factor $1/R_k$.
- **(5.4)** FG isolation: $\tau<\frac12d_{k,\sigma}$, with $d$ as displayed (at leading order in $\varkappa_k$).
  - The lower branch ($\sigma\gamma<0$) is isolated for every $\gamma\neq0$, every $L$ and every $N_f$.
  - For $N_f=1$ the upper branch is isolated for every $\gamma\neq0$.
  - For $N_f\ge2$ the upper level lies below every excited lower-branch level iff $\Delta_b<\varepsilon^-_1$ (in R1: $2n|\gamma|M_k<\varepsilon_1$); beyond, it crosses lower-branch levels at isolated values of $\gamma$.
  - Isolation fails as $\gamma\to0$ (both branches) and as $L\to\infty$ at fixed $n,\gamma$ (upper branch).
- **(5.5)** Weak-mark expansions of $\varphi_g$, $\varepsilon_0$, $R_k$, $C^{\rm ev}_k=-n\gamma^2M_k^2\ell_0/t_f+O(\gamma^4)$, $a^2$ and $J^{\rm exc}$, through the displayed orders, under R1 (FG) or (6.4) at $\tau=0$ ((a), (c)).
- **(5.6)** Item 1. Under (5.4) and R1, $E''_{k,\sigma}(0)=\frac{\tau^2}{n\sigma\gamma M_k}[1-\gamma^2M_k^2K_L+O(N_f^2\varkappa_k^3)]+O(\tau^4/d^3_{k,\sigma})$, with $\gamma^2M_k^2K_L\simeq(N_f+1)\varkappa_k^2/180$. The leading term is the curvature of a Model D body with half-gap $n\gamma M_k$.
- **(5.7)** Item 2 at leading order. $\mu_{k,\sigma}=\mathrm{Cost}_{k,\sigma}/v^2+O(\gamma^2)$ for every level and branch, with $v=\tau$ for (a) and FG and $v=\tau(1+\gamma n)$ for (c). The held cost enters; the dressed level gives the same answer. $v$ is the slope at $P\to0$ of the band $\pm v\lvert\sin P\rvert$ of the mean-field motion term alone. No level attains it, and it is independent of $t_f$, so it is not fixed by the field band.
- **(5.8)** Item 2 at order $\gamma^2$, FG. $\mu_{k,\sigma}-\mathrm{Cost}_{k,\sigma}/\tau^2=n\ell_0\gamma^2M_k^2/(t_f\tau^2)+O(\gamma^3)$. Branch differences agree through $O(\gamma^2)$, but level differences differ by $n\ell_0\gamma^2(M_k^2-M_{k'}^2)/(t_f\tau^2)$. There is no single $v$ at order $\gamma^2$ (in R1).
- **(5.9)** Item 2 at order $\gamma^2$, (a) and (c). $D_{k,\sigma}$ is given by (5.9), at leading order in $\tau$. In the limits $t_f\gg M_kL^2$ and $t_f\ll M_k$ no change of $v$ makes it level- and branch-independent, so there is no single $v$ at order $\gamma^2$. For other $t_f$ the condition can hold only at isolated values of $t_f$.
- **(5.10)** Item 3, at first order in $g_s$. $E''_{k,\sigma}(0)\Delta W_{k,\sigma}=\tau^2F\Lambda[1+\sigma\gamma M_k\Xi+O(\gamma^2)]$, with $\Lambda=1$ (FG), $n\gamma(1\mp\gamma n)$ ((a), (c)). It is the same for all levels and both branches at leading order. The first level and branch dependence is $\sigma\gamma M_k\Xi$ at relative order $\gamma$, of size $O(\varkappa_k)$, with the same $\Xi$ for the three couplings. (7.7) applies to FG with $E''$ of (5.2).
- **(5.11)** Item 4.
  - $v$ is independent of $t_f$.
  - For $N_f\ge2$, the FG upper level lies below the excited lower-branch levels only for $t_f>n|\gamma|M_k/(1-\cos\frac{2\pi}L)$ (leading order in $\varkappa_k$).
  - The first level dependence stays at order $\gamma^2$, with the relative sizes displayed. It vanishes as $1/t_f$ for large $t_f$, and in (a) and (c) it grows as $1/t_f^2$ for $t_f\ll M_k$.
  - For $t_f\ll\tau$ the FG upper branch is not isolated. The FG lower branch is isolated for $\tau\ll|\gamma|M_k$, and there $\mu\to\infty$ as $t_f\to0$ at finite cost.
  - At fixed $n$ and $\gamma$, (5.6)–(5.10) have no $L\to\infty$ limit (R1 fails); (5.2) and (5.3) still hold for the lower branch.

## Consistency checks

1. **$\gamma\to0$ and mean field for (a), (c) against (6.10).** With $a=1+\theta_c\gamma n$, $J^{\rm exc}=0$ and $R_k=M_k(1+\gamma n)$, (5.2)–(5.3) give $\sigma\tau^2/(M_k(1+\gamma n))$ for (a) and $\sigma\tau^2(1+\gamma n)/M_k$ for (c). These are the mean-field parts of (6.10), and both reduce to $\sigma\tau^2/M_k$ at $\gamma=0$. Passed.
2. **FG at mean field against a body with a rest term.** The leading term of (5.6), $\tau^2/(\sigma n\gamma M_k)$, is the curvature at $P=0$ of $\pm(\tilde M^2+\tau^2\sin^2P)^{1/2}$ with $\tilde M=n\gamma M_k$. That body's held cost $\sigma\tilde M$ equals the leading FG cost. Passed.
3. **Dimensions.** $\tau,t_f,M_k,g_s$, costs and $E''$ are contract units, and $\gamma,n,P,\ell,F$ are dimensionless. $K_L\propto t_f^{-2}$, and $\tau^2D/(\sigma R)$ and $\gamma M_k\Xi$ are dimensionless. $E''\Delta W=\tau^2F\Lambda$ has units of contract squared. Passed.

## Open issues

- The error term of (7.7) for FG is not re-derived.
- FG beyond R1 (strong mark), including the lower branch as $L\to\infty$ at fixed $n$: (5.2) holds there, but items 2 and 3 are not evaluated.
- (5.9) is derived at $\tau\to0$ only; the finite-$\tau$ bracket of (6.12) is not evaluated, and (5.9) is not checked numerically.
- $N_f\ge2$ and the FG upper branch beyond $2n|\gamma|M_k=\varepsilon_1$ are not checked numerically.
- The $O(\gamma)$ term of (5.10) has a control only in a wider class.
- The relation of $v=\tau$ to the maximal speed of 03-ilang-space is not quoted here and not used.

## Code

`code/v1/check_full_grip.py` (check) does the following:
- builds the sector contract (5.1) for FG with $N_f=1$, and verifies it against the full contract at $L=6$ (eigenvalues agree to $4\times10^{-15}$);
- for $L=8,13$, $t_f=1$, $M_k\in\{1,1.4\}$ ($m=1$, $N=2$, $\lambda_0=5\pi/2$), $\gamma\in\{0.01,0.02,0.3\}$ and both branches, computes the exact curvature of the dressed level at $P=0$, by second-order perturbation in $P$ from a full diagonalization, at $\tau=10^{-5}$ and $\tau=d/5$, together with the exact isolation distance $d$;
- compares it with (5.2) and (5.6);
- compares $\tau^2\mu-\mathrm{Cost}$, its level and branch differences, and $E''\Delta W/(\tau^2F)$ with (5.8) and (5.10), and $\Delta W$ with (3.13).

Output: `code/v1/output/check_full_grip.txt`. Results:
- (5.2): agreement to $\le1.4\times10^{-12}$ at $\tau=10^{-5}$ ($\le5\times10^{-10}$ at $\gamma=0.3$, $\varkappa_k\le5.5$); at $\tau=d/5$ to $\le9\times10^{-9}$ ($\gamma\le0.02$) and $\le1.1\times10^{-3}$ ($\gamma=0.3$).
- (5.6): agreement to $\le1.2\times10^{-5}$ for $N_f\varkappa_k\le0.36$, with deviation $\propto\gamma^3$; up to $0.1$ at $\gamma=0.3$ (outside R1).
- (5.8): $\tau^2\mu-\mathrm{Cost}$ within $2.4\%$ (the deviation is branch-odd, $O(\gamma^3)$); the level difference $k=1$ minus $k=0$ within $3.2\%$; $\tau^2(\mu_+-\mu_-)$ equals $\mathrm{Cost}_+-\mathrm{Cost}_-$ to $\le7\times10^{-4}$ of the latter.
- (5.10): the branch-odd part of $E''\Delta W/(\tau^2F)-1$ equals $\gamma M_k\Xi$ to $\le0.2\%$ ($\Xi=-0.167$ for $L=8$, $-0.808$ for $L=13$, places $r=2,3$); the branch-even part is $O(\gamma^2)$; (3.13) reproduces $\Delta W$ to $O(C^3)$.

## Methods used

- sector decomposition by joint translation; reflection symmetry
- Rayleigh–Schrödinger perturbation theory; Kato's isolation criterion
- spectral decomposition of resolvents; Franck–Condon overlaps of product states
- Perron–Frobenius; secular equation of a rank-one perturbation
- Fourier sums on the ring
- exact diagonalization; second-order perturbation in $P$ (numerical check)

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